7r^2+10r-6=2

Solution for 7r^2+10r-6=2 equation:

7r^2+10r-6=2

We move all terms to the left:

7r^2+10r-6-(2)=0

We add all the numbers together, and all the variables

7r^2+10r-8=0

a = 7; b = 10; c = -8;
Δ = b2-4ac
Δ = 102-4·7·(-8)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-18}{2*7}=\frac{-28}{14}
=-2
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+18}{2*7}=\frac{8}{14}
=4/7
$